3.6^2+x^2=7.4^2

Solution for 3.6^2+x^2=7.4^2 equation:

3.6^2+x^2=7.4^2

We move all terms to the left:

3.6^2+x^2-(7.4^2)=0

We add all the numbers together, and all the variables

x^2-41.8=0

a = 1; b = 0; c = -41.8;
Δ = b2-4ac
Δ = 02-4·1·(-41.8)
Δ = 167.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{167.2}}{2*1}=\frac{0-\sqrt{167.2}}{2}
=-\frac{\sqrt{}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{167.2}}{2*1}=\frac{0+\sqrt{167.2}}{2}
=\frac{\sqrt{}}{2}
$